Sunday, 14 April 2013

i-Hack 2013 challange3

This challenge is quite simple, an xor'ed text is stored in the stack. Xor-ing these static values would yield us the flag:

s = "\xcc\xa5\xe9\xea\xf3\xe0\xa5\xc8\xe4\xe9\xe4\xe6\xe6\xe4\xa4"
r = ""
for i in s:
 r += chr(ord(i) ^ 0x85)
print r
I love Malacca!

1 comment:

  1. I'm waiting for this post. Kudos for solving it :)